Can someone help me figure this out please

For this case, a rectangular triangle is observed. We must find the value of the base of the triangle through the Pythagorean theorem that states:
[tex]c = \sqrt {a ^ 2 + b ^ 2}[/tex]
Where:
[tex]c = 36 \ m\\a = 34 \ m\\b = \sqrt {c ^ 2-a ^ 2}[/tex]
Substituting:
[tex]b = \sqrt {36 ^ 2-34 ^ 2}\\b = \sqrt {1296-1156}\\b = \sqrt {140}\\b = 11.83215957[/tex]
Rounding:
11.8
Answer:
11.8 meters
Answer:
y = 11.832 ≅ 11.8 m
Step-by-step explanation:
We have given a triangle whose two sides are given.
Perpendicular = 34m and Hypotenuse = 36m
We have to find the base.
Base = y = ?
Using pythagorean theorem, we have
(base)²+(Perpendicular)² = (hypotenuse)²
Putting given values in above formula, we have
y² + (34)² = (36)²
y²+1156 = 1296
y² = 1296-1156
y² = 140
y = 11.832 ≅ 11.8 m which is the answer.