Answer:
Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b) where a=3x and b=8
.
(3x+8)(3x−8)
Step-by-step explanation:
Assignment: [tex]\bold{Factor \ Equation: \ 9x^2-64}[/tex]
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Answer: [tex]\boxed{\bold{\left(3x+8\right)\left(3x-8\right)}}[/tex]
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Explanation: [tex]\downarrow\downarrow\downarrow[/tex]
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[ Step One ] Rewrite [tex]\bold{9x^2-64}[/tex]
[tex]\bold{\left(3x\right)^2-8^2}[/tex]
[ Step Two ] Rewrite Equation
[tex]\bold{\left(3x\right)^2-8^2}[/tex]
[ Step Three ] Apply Difference Of Two Squares Formula
Note: [tex]\bold{Difference \ Of \ Two \ Squares \ Formula: \ x^2-y^2=\left(x+y\right)\left(x-y\right)}[/tex]
[tex]\bold{\left(3x\right)^2-8^2=\left(3x+8\right)\left(3x-8\right)}[/tex]
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[tex]\bold{\left(3x+8\right)\left(3x-8\right)}[/tex]
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[tex]\bold{\rightarrow Mordancy \leftarrow}[/tex]
