Respuesta :

carlosego

Answer: option a

Step-by-step explanation:

You have that (fg)(x) indicates that you must multiply f(x) and g(x).

Keeping the above mind, you have that:

[tex]\lim_{-2 \to \infty} (fg)(x)\\ \lim_{-2 \to \infty}(fg)(x)= (5*2)\\ \lim_{-2 \to \infty}(fg)(x)=10[/tex]

You must substitute x=-2, but there is not x, therefore, the answer is: 10 (option a).

kudzordzifrancis

ANSWER

a. 10

EXPLANATION

Apply the following property of limits.

The product of the limits is the same as the limits of the limits.

[tex]lim_{x\to -2}(fg)(x)=lim_{x \to -2}f(x)\times \: lim_{x\to -2}g(x)[/tex]

This implies that,

[tex]lim_{x\to -2}(fg)(x)=5\times 2[/tex]

Multiply to get,

[tex]lim_{x\to -2}(fg)(x)=10[/tex]

The correct choice is A.

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