Following are the solution to the given points:
For point a)
[tex]H_0: ? = 0\ mpg\\\\ H_a: ?\ ?\ 0\ mpg [/tex]
For point b)
count [tex]n=20\\\\[/tex]
mean [tex] \bar{x}=2.670\\[/tex]
sample variance [tex]S=7.410\\\\[/tex]
sample standard deviation [tex]\sigma=2.722\\\\[/tex]
Calculating the test statistic:
[tex]\to Z=\frac{(\bar{x}-\mu)}{(\frac{s}{\sqrt{n}})}\\\\[/tex]
[tex]=\frac{(2.67-0)}{(\frac{3}{\sqrt{20}})}\\\\ =\frac{(2.67)}{(\frac{3}{\sqrt{2\times 2 \times 5}})}\\\\ =\frac{(2.67)}{(\frac{3}{2\sqrt{5}})}\\\\ =(2.67)\times \frac{2\sqrt{5}}{3}\\\\ =0.89 \times 2\sqrt{5} \\\\ = 1.78\sqrt{5}\\\\= 3.98 [/tex]
It is a two-tailed test. So the p-value[tex]= 2\times P(Z>3.98) =0[/tex] (from the standard normal table).
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