Assignment: [tex]\bold{Solve \ Equation: \ x^2-28-3x}[/tex]
<><><><><><><>
Answer: [tex]\boxed{\bold{\left(x+4\right)\left(x-7\right)}}[/tex]
<><><><><><><>
Explanation: [tex]\downarrow\downarrow\downarrow[/tex]
<><><><><><><>
[ Step One ] Write Equation In Standard Form: [tex]\bold{ax^2+bx+c}[/tex]
[tex]\bold{x^2-3x-28}[/tex]
[ Step Two ] Break Expression Into Groups
[tex]\bold{\left(x^2+4x\right)+\left(-7x-28\right)}[/tex]
[ Step Three ] Factor
Factor Out [tex]\bold{x}[/tex] From [tex]\bold{x^2+4x: \ x\left(x+4\right)}[/tex]
Factor Out [tex]\bold{-7}[/tex] From [tex]\bold{-7x-28: \ -7\left(x+4\right)}[/tex]
[ Step Four ] Rewrite Equation
[tex]\bold{x\left(x+4\right)-7\left(x+4\right)}[/tex]
[ Step Five ] Factor Out Common Term [tex]\bold{x+4}[/tex]
[tex]\bold{\left(x+4\right)\left(x-7\right)}[/tex]
<><><><><><><>
[tex]\bold{\rightarrow Mordancy \leftarrow}[/tex]
