Which equation shows a correct relationship of trigonometric functions?


[tex]\frac{sin(x)}{cos(y)} = 1[/tex]
Try it on a calculator.
x + y = 90
if x = 30 and y = 60
[tex]\frac{sin(30)}{cos(60)}= 1[/tex]
Answer:
[tex]\frac{\sin(x)}{\cos(y)}=1[/tex]
Step-by-step explanation:
From the given right triangle.
[tex]x+y=90\degree[/tex]
This implies that;
[tex]\sin(x)=\cos(y)[/tex]
Because the two angles are complementary.
We divide both sides by [tex]\cos(y)[/tex] to obtain;
[tex]\frac{\sin(x)}{\cos(y)}=\frac{\cos(y)}{\cos(y)}[/tex]
We simplify to get;
[tex]\frac{\sin(x)}{\cos(y)}=1[/tex]