Answer:
[tex]\large\boxed{c(3)=3}[/tex]
Step-by-step explanation:
[tex]\left\{\begin{array}{ccc}c(1)=\dfrac{3}{16}\\\\c(n)=c(n-1)\cdot 4\end{array}\right[/tex]
Put n = 2 and next n = 3 to the recursive formula:
[tex]c(2)=c(2-1)\cdot4=c(1)\cdot4\to c(2)=\dfrac{3}{16}\cdot4=\dfrac{3}{4}\\\\c(3)=c(3-1)\cdot4=c(2)\cdot4\to c(3)=\dfrac{3}{4}\cdot4=3[/tex]
The 3rd term is 4.
A sequence is an enumerated collection of objects in which repetitions are allowed and order matters.
Given:
c(1) = 3/16
and, c(n)=c(n−1)⋅4
c(2)= c(1)*4
c(2) = 3/16*4
c(2)= 3/4
and, c(3) = c(2)*4
c(3) = 3/4 *4
c(3)=4
Hence, the 3rd term is 4.
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