Need help with rational function question for precalculus

Answer:
Answers: 1), 2), 3).
Step-by-step explanation:
Note that when we say [tex]x \to a^-[/tex], we mean "as x tends to a from the left hand side". That is, what is the function doing when "x approaches a from the left side". In much the same way, we say [tex]x \to a^+[/tex] to imply what the function is doing when "x approaches from the right side".
So, when [tex]x \to 3^-[/tex], we are looking at the point around x = 3, but from the left side. From the graph, we see that, from the left side of 3, the graph is approaching a fairly big number. So, we see that: "As [tex]x \to 3^-[/tex], [tex]f(x) \to \infty[/tex]".
In much the same way:
"As [tex]x \to 3^+[/tex], [tex]f(x) \to -\infty[/tex]".
"As [tex]x \to \infty[/tex], [tex]f(x) \to 2[/tex]".