The volume V of a given mass of a gas varies directly as a temperature T and inversely as the pressure P. If V=231cm^3 when T=300 degrees Kelvin and P=20lb/cm^2, what is the volume when T=484 degrees Kelvin and P=22lb/cm^2?

Respuesta :

Answer:

V = 338.8 [tex]cm^3[/tex]

Step-by-step explanation:

Basically manipulate the ideal gas law.

PV = nRT

We know n and R are constant so we can cross that out. We get:

PV = T or [tex]\frac{PV}{T}[/tex]

Let's plug in the values to get:

[tex]\frac{20*231}{300} =\frac{22*V}{484}[/tex]

We simplify them to get:

[tex]\frac{4620}{300} =\frac{22V}{484}[/tex]

We cross multiply:

[tex]4620*484 = 300*22V[/tex]

Simplify:

[tex]2,236,080 = 6,600V[/tex]

Solve for V by dividing both sides by 6,600.

Hope it helps! (:

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