adalchow10
contestada

Help me ASAP please :( Type the correct answer in each box. Write your answers as fractions, using / as the fraction bar, and write the greater value first.

Help me ASAP please Type the correct answer in each box Write your answers as fractions using as the fraction bar and write the greater value first class=

Respuesta :

Answer:

see explanation

Step-by-step explanation:

Using the laws of logarithms

• log x - log y = log([tex]\frac{x}{y}[/tex])

• [tex]log_{b}[/tex] x = n ⇔ x = [tex]b^{n}[/tex]

Hence

[tex]log_{x}[/tex]( [tex]\frac{8x-3}{4}[/tex] ) = 2, hence

[tex]\frac{8x-3}{4}[/tex] = x² ( multiply both sides by 4 )

8x - 3 = 4x² ← rearrange into standard form

Subtract 8x - 3 from both sides

4x² - 8x  + 3 = 0 ← in standard form

(2x - 1)(2x - 3) = 0 ← in factored form

Equate each factor to zero and solve for x

2x - 1 = 0 ⇒ 2x = 1 ⇒ x = [tex]\frac{1}{2}[/tex]

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = [tex]\frac{3}{2}[/tex]

The value of x is 3/2 or 1/2 in the provided logarithmic equation after applying the log property.

What is a logarithm?

It is another way to represent the power of numbers, and we say that 'b' is the logarithm of 'c' with base 'a' if and only if 'a' to the power 'b' equals 'c'.

[tex]\rm a^b = c\\log_ac =b[/tex]

We have a logarithmic expression:

[tex]\rm log_x\left(8x-3\right)-log_x4=\:2[/tex]

[tex]\rm \log _x\left(8x-3\right)-\log _x\left(4\right)+\log _x\left(4\right)=2+\log _x\left(4\right)[/tex]

8x - 3 = 4x²

x = 3/2, x = 1/2

Thus, the value of x is 3/2 or 1/2 in the provided logarithmic equation after applying the log property.

Learn more about the Logarithm here:

brainly.com/question/163125

#SPJ2

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE

Otras preguntas