Respuesta :

abhaysilver1

Here is your answer

Using Pythagoras' theorem

we know the

Hypotenuse^2= base^2+perpendicular^2

So here,

[tex]{x}^{2}={9}^{2}+{3}^{2}[/tex]

[tex]{x}^{2}=81+9[/tex]

[tex]{x}^{2}=90[/tex]

[tex]x=\sqrt{90}[/tex]

[tex]x=3\sqrt{10}[/tex]

HOPE IT IS USEFUL

Answer:

x = 3[tex]\sqrt{10}[/tex]

Step-by-step explanation:

Since the triangle is right use Pythagoras' identity to solve for the hypotenuse x, that is

x² = 9² + 3³ = 81 + 9 = 90

Take the square root of both sides

x = [tex]\sqrt{90}[/tex] = [tex]\sqrt{9(10)}[/tex] = 3[tex]\sqrt{10}[/tex] ← exact value

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