[tex] \bold{ANSWER}[/tex]
The given figure have two trapezium joined to a same base.
Since, we know
Area of trapezium = [tex] \boxed{ \frac{1}{2} \times sum \: of \: parallel \: sides \times height}[/tex]
On placing values,
◼For first trapezium
Area of trapezium = [tex] \boxed{ \frac{1}{2} \times (30 + 20) \times 12}[/tex]
Area of trapezium = [tex] \boxed{ \frac{1}{2} \times 50 \times 12}[/tex]
Area of trapezium = 25 ×12 =300cm²
◼For second trapezium
Area of trapezium = [tex] \boxed{ \frac{1}{2} \times (30 + 20) \times 12}[/tex]
Area of trapezium = [tex] \boxed{ \frac{1}{2} \times 50 \times 12}[/tex]
Area of trapezium = 25 ×12 =300cm²
TOTAL AREA = 300 + 300 =600cm²
