Hello!
The answer is: c.) [tex]5.3x10^{3}Kg.\frac{m}{s}[/tex] (to the right direction)
Why?
Since it's an inelastic collision, the kinetic energy change after the collision.
Momentum equation is equal to:
[tex]p=m*v[/tex]
Where:
[tex]p=momentum\\m=mass\\v=velocity[/tex]
Bus momentum: (going to the right)
[tex]mass=1.5x10^{3}kg\\velocity=20\frac{m}{s}[/tex]
[tex]p=1.5x10^{3}kg*20\frac{m}{s}=30x10^{3}Kg.\frac{m}{s}[/tex]
Car momentum: (going to the left)
[tex]mass=9.5x10^{2}kg\\velocity=-26\frac{m}{s}[/tex]
[tex]p=9.5x10^{2}kg*-26\frac{m}{s}=-24.7x10^{3}Kg.\frac{m}{s}[/tex]
The total momentum will be:
[tex]T=BusMomentum+CarMomentum\\\\T=30x10^{3}Kg.\frac{m}{s}-24.7x10^{3}Kg.\frac{m}{s}=5.3x10^{3}Kg.\frac{m}{s}[/tex]
So, the total momentum is [tex]5.3x10^{3}Kg.\frac{m}{s}[/tex] (to the right direction)
Have a nice day!
