Respuesta :

mixter17

Hello!

The answer is:

[tex]y=8-5x[/tex]

Why?

If we want to find an equation of a line parallel to the given line, we must remember that parallel lines has the same slope.

So,

Line equation is:

[tex]y=mx+b[/tex]

Where:

[tex]m=LineSlope[/tex]

[tex]b=y-axisIntercept[/tex]

So, we are given the function:

[tex]y=9-5x[/tex]

Where:

m=-5

Also, we are given the point where the line passes through (0,8), we can use it to find "b"

[tex]y=b-5x\\y+5x=b\\b=8+5(0)=8[/tex]

So, the equation will be:

[tex]y=8-5x[/tex]

To prove if we are right, let's substitute (0,8):

[tex]8=8-5(0)[/tex]

[tex]8=8-0[/tex]

[tex]8=8[/tex]

Have a nice day!

zainebamir540

Answer:

y =  8-5x is equation of line that is parallel to y = 9-5x and passing through (0,8).

Step-by-step explanation:

We have given a equation of line and a point.

y=9−5x and (x₁,y₁)=  (0, 8)

We have to find equation of line that is parallel to given equation of line and passing through given point.

y-y₁ = m(x-x₁) is point-slope form of equation of line where m is slope of line.

Since, we know that parallel line have equal slope of line.

Given equation has slope equal to -5.

Parallel line also has slope equal to -5.

m = -5

Putting values in point-slope form of equation , we have

y-(8) = -5(x-0)

y-8 = -5(x)

y-8= -5x

y =  8-5x is equation of line that is parallel to y = 9-5x and passing through (0,8).

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