The first equation of the system is multiplied by 4. By what number would you multiply the second equation in order to eliminate the x variable by adding?
3x-2y=4
4x+5y=28

Since you've multiplied the firs equation by 4 you have a 12x. So you must found a number that multiplied by the 4x in the second equation will result in -12x. Concerning that the negative signal turns the number to negative, you come to the answer -3 (Minus three)

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luana luana · Answer 2 · 2014-09-19T01:22:11+02:00

luana luana

19-09-2014

[tex] \left \{ {{3x-2y=4\ \ \ |*4} \atop {4x+5y=28}} \right. \\\\ \left \{ {{12x-8y=16} \atop {4x+5y=28}} \right.\\\\To\ eliminate\ by\ adding\ multiply\ second\ equation\ by\ -3\ to\\ obtain\ -12x\\\\ \left \{ {{12x-8y=16} \atop {-12x-15y=-84}} \right.\\+----\\Addition:\\\\ -8y-15y=16-84\\ -33y=-68\\ y=\frac{68}{33}\\ 4x=28-5y\\ x=\frac{28-5y}{4}=\frac{28-5*\frac{68}{33}}{4}=\frac{1}{4} [/tex]

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The first equation of the system is multiplied by 4. By what number would you multiply the second equation in order to eliminate the x variable by adding? 3x-2y=4 4x+5y=28

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The first equation of the system is multiplied by 4. By what number would you multiply the second equation in order to eliminate the x variable by adding?
3x-2y=4
4x+5y=28