need help:

Use the given conditions to write an equation for each line in point-slope form.

Passing through (2, -3) and perpendicular to the line whose equation is y = 1/5 x + 6.
Question 11 options:

y + 8 = 5(x - 6)

y - 3 = -5(x + 20)

y + 3 = -5(x - 2)

y - 3 = -5(x + 5)

Where 'm' represents the slope and ([tex]x_{1},y_{1}[/tex]) represent a point on the line. Since the line is perpendicular to the line with the equation: y = 1/5x + 6, then the slope of the new line is the opposite reciprocal of the given slope. So, 1/5 becomes -5.

Using m = -5 and point (2, -3):

y + 3 = -5(x - 2)

need help: Use the given conditions to write an equation for each line in point-slope form. Passing through (2, -3) and perpendicular to the line whose equation is y = 1/5 x + 6. Question 11 options: y + 8 = 5(x - 6) y - 3 = -5(x + 20) y + 3 = -5(x - 2) y - 3 = -5(x + 5)

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need help:

Use the given conditions to write an equation for each line in point-slope form.

Passing through (2, -3) and perpendicular to the line whose equation is y = 1/5 x + 6.
Question 11 options:

y + 8 = 5(x - 6)

y - 3 = -5(x + 20)

y + 3 = -5(x - 2)

y - 3 = -5(x + 5)