The equation of a line is 2/5x+1/10y=2
The x-intercept of the line is and it’s y-intercept is

For this case we have the following equation of a line:
[tex]\frac {2} {5} x + \frac {1} {10} y = 2[/tex]
To find the point of intersection with the x axis, we make y = 0:
[tex]\frac {2} {5} x + \frac {1} {10} (0) = 2\\\frac {2} {5} x = 2[/tex]
We clear the value of "x":
[tex]x = \frac {2 * 5} {2}\\x = 5[/tex]
So, the x-intercept of the line is 5.
To find the point of intersection with the y axis, we make x = 0:
[tex]\frac {2} {5} (0) + \frac {1} {10} y = 2\\\frac {1} {10} y = 2[/tex]
We clear the value of "and":
[tex]y = \frac {10 * 2} {1}\\y = 20[/tex]
So, the y-intercept of the line is 20.
Answer:
[tex]x = 5\\y = 20[/tex]
Answer:
x intercept is 5
y intercept is 20
Step-by-step explanation:
When a line intersects the x axis, the y coordinate is zero. therefore we substitute y with zero to get the following equation.
2/5x+ 1/10(0)= 2
solving the equation,
2/5x=2
x=2×5/2
Thus x=5
x intercept is therefore 5
When a line intersects the y axis, the x coordinate is zero
To get the y intercept we substitute x with zero.
2/5(0)+1/10y=2
solving the equation,
1/10y=2
y=2×10/1
y=20