For this case, we have that by definition, the distance between two points is given by:
[tex]d = \sqrt {(x_ {2} -x_ {1}) ^ 2+ (y_ {2} -y_ {1}) ^ 2}[/tex]
We have to:
[tex]A: (x_ {1}, y_ {1}) = (- 2,3)\\A ':( x_ {2}, y_ {2}) = (x + 4, y + 2) = (- 2 + 4, 3 + 2) = (2,5)[/tex]
Substituting:
[tex]d = \sqrt {(2 - (- 2)) ^ 2+ (5-3) ^ 2}\\d = \sqrt {(4) ^ 2 + (2) ^ 2}\\d = \sqrt {16 + 4}\\d = \sqrt {20}[/tex]
Answer:
[tex]d = \sqrt {20}[/tex]
Answer:
Distance between A and A' is 2√5.
Step-by-step explanation:
The given point A is translated to A' by using T: (x, y) → (x + 4, y+2).
We have to calculate the distance from A and A'
if A is (-2, 3) then the translated point A' will be ( -2+4, 3+2)≅(2, 5)
Now we can calculate the distance between A and A' by using the distance formula
Distance = √[(-2-2)²+(3-5)²] = √(-4)²+(-2)² = √16+4 = √20
= 2√5
So the correct answer is distance = 2√5.
