Answer: [tex]\frac{2ae^{3}}{3bd}[/tex]
Step-by-step explanation:
1. You have the following expression given in the problem above:
[tex]\frac{2ab^{-1}}{3e^{-3}d}[/tex]
2. Then, according to the Negative exponent rule, you have that:
[tex]a^{-n}=\frac{1}{a^{n}}[/tex]
3. So, based on the rule shown above, the negative exponents indicates that [tex]b[/tex] must be in the denominator and [tex]e^{3}[/tex] must be in the numerator. Therefore, you obtain the following expression:
[tex]\frac{2ae^{3}}{3bd}[/tex]
