In this problem we have the electric field intensity E:
E = 6.5 × [tex]10^4[/tex] newtons/coulomb
We have the magnitude of the load:
q = 6.4 × [tex]10 ^{-19}[/tex] coulombs
We also have the distance d that the load moved in a direction parallel to the field 1.2 × [tex]10^{-2}[/tex] meters.
We know that the electric potential energy (PE) is:
PE = qEd
So:
PE = (6.4 × [tex]10^{-19}[/tex])(6.5 × [tex]10^4[/tex])(1.2 × [tex]10^{-2}[/tex])
PE = 5.0 x [tex]10^{-16}[/tex] joules
None of the options shown is correct.
