As we know that
[tex]\frac{1}{d_i} + \frac{1}{d_0} = \frac{1}{f}[/tex]
here we know that
[tex]d_0 = 6 cm[/tex]
[tex]f = 10 cm[/tex]
now from above equation we have
[tex]\frac{1}{d_i} + \frac{1}{6} = \frac{1}{10}[/tex]
[tex]d_i = -15 cm[/tex]
so image will form on left side of lens at a distance of 15 cm
This image will be magnified and virtual image
Ray diagram is attached below here
