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9. A biologist is researching a newly-discovered species of bacteria. At time t = 0 hours, he puts seventy-five bacteria into what he has determined to be a favorable growth medium. Four hours later, he measures 325 bacteria. Assuming exponential growth, what is the growth constant "k" for the bacteria? (Round k to two decimal places.)

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Step-by-step explanation:

A biologist is researching a newly-discovered species of bacteria.

at time t=0 hours, he puts one hundred bacteria into what he has determined to

be a favorable growth medium.

Six hours later, he measures 450 bacteria.

Find an exponential equation that approximates the information.

:

find k, the growth factor

100*(2^(6/k)) = 450

Divide both sides by 100

2^(6/k) = 4.5

use logs here

log(2^(6/k)) = log(4.5)

:

log(2) = log(4.5)

=  

= 2.17

k =  

k = 2.765 is the growth factor

:

A = Ao*2^(t/2.765), the exponential equation

where

Ao = initial amt

A = amt after t hrs

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