Answer: The answer is [tex]\dfrac{1}{2}.[/tex]
Step-by-step explanation: Given that Cooper is studying two fractions and both are less than 1. The first fraction has a denominator of 4 and rounds to 1.
So, let the first fraction be
[tex]F-f=\dfrac{3}{4}=0.75,[/tex]
and surely it will rounds to 1.
Also, the second fraction has a denominator of 6 and the same numerator as the first fraction.
Therefore, the second fraction will be
[tex]F_s=\dfrac{3}{6}=\dfrac{1}{2}.[/tex]
Thus, the second fraction will be closest to [tex]\dfrac{1}{2}.[/tex]
