Answer:
The volume of O2 gas = 1.44 L
Explanation:
Given:
Initial volume of O2 gas, V1 = 3.60 L
Initial pressure, P1 = 1.00 atm
Final pressure, P2 = 2.50 atm
To determine:
Final volume of O2 gas, V2
Explanation:
Based on the ideal gas equation
[tex]PV = nRT\\[/tex]
where n = moles of gas
R = gas constant, T = temperature
At constant T, the above equation becomes:
PV = constant
[tex]i.e.\ P1V1= P2V2\\\\V2 = \frac{P1V1}{P2} = \frac{1.00atm*3.60 L}{2.50atm} =1.44\ L[/tex]
