Answer:
The constraints are
[tex]x+y\geq 14[/tex]
[tex]2y+x\leq 20[/tex]
[tex]x\geq 0[/tex]
[tex]y\geq 0[/tex]
Step-by-step explanation:
Let
x-------> the number of dozens of regular pretzels.
y-------> the number of dozens of whole-grain pretzels.
we know that
[tex]x+y\geq 14[/tex] --------> inequality A
[tex]2y+x\leq 20[/tex] -------> inequality B
[tex]x\geq 0[/tex] -------> inequality C (cannot be a negative number)
[tex]y\geq 0[/tex] ------> inequality D (cannot be a negative number)
The solution is the triangular shaded area
see the attached figure