Answer: Option 'C' is correct.
Step-by-step explanation:
Since we have given that
[tex]\frac{1}{6}(6x+12)-\frac{1}{2}(4x+2)=-x+1[/tex]
If we substitute x= 2 into the expression:
[tex]\frac{1}{6}(6\times 2+12)-\frac{1}{2}(4\times 2+2)=-2+1=-1\\\\\frac{1}{6}(24)-\frac{1}{2}(10)=-1\\\\4-5=-1\\\\-1=-1[/tex]
If we put x = 6 into the expression:
[tex]\frac{1}{6}(6\times 6+12)-\frac{1}{2}(4\times 6+2)=-6+1=-5\\\\\frac{1}{6}(48)-\frac{1}{2}(26)=-5\\\\8-13=-5\\\\=-5=-5[/tex]
Hence, Both are correct because after the substituting the same value into both expression, the result is same.
Hence, Option 'C' is correct.
