Answer:
Step-by-step explanation:
Given that in a triangle ABC, AB = 28, BC = 24 and angle C =91,
We have to find measure of angle B.
Since three measurements are given, we can solve the triangle easily
Use the sine formula for triangles.
[tex]\frac{c}{SinC} =\frac{b}{Sin B}=\frac{a}{Sin A}[/tex]
[tex]A = arcsin(\frac{asinC}{c} )=58.98[/tex]
Since sum of 3 angles is 180, we calculate B easily
Angle B = 180-(A+C)
= 180-(91+58.98)
=30.02