Area of rectangle = 10cm²
We know that, Area of rectangle = lb
lb = 10
Let l = x cm. Then b = 10/x cm.
Perimeter of rectangle
[tex] = 2(l + b) \\ = 2(x + \frac{10}{x}) \\ = \frac{2 {x}^{2} + 10 }{x}cm.[/tex]
But, this rectangle can't have 12 as its perimeter because Sides have to be factors of 10.If l = 5cm and b = 2cm then it will have perimeter 14cm.If l = 10cm and b = 1cm then it will have perimeter 22cm.
Hope this will help you.
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