if an object is on the surface of Moon then the force of gravitation is given as
[tex]F_1 = \frac{GM(6kg)}{R^2}[/tex]
here
M = mass of moon
R = radius of moon
now in other case we have the same object orbiting at distance 6 times greater than the radius of moon
so the force of gravitation is given as
[tex]F_2 = \frac{GM(6kg)}{(6R)^2}[/tex]
now we will find the ratio of two forces
[tex]\frac{F_1}{F_2} = \frac{1}{1/36} = 36 [/tex]
so here the force of gravity on orbiting object is 36 times less than the object which is placed on the surface of moon
