The diagram below represents the net of a triangular prism. What is the surface area of the triangular prism?

Answer:
(C)
Step-by-step explanation:
The diagram is divided ninto 5 parts that is rectangles ABCD, CHGD, GFEH and triangles CIH and DGJ.
Area of rectangle ABCD= [tex]l{\times}b[/tex]
=[tex]12{\times}6=72cm^{2}[/tex]
Area rectangle CDHG= [tex]l{\times}b[/tex]
=[tex]12{\times}8=96cm^{2}[/tex]
Area rectangle HGFE= [tex]l{\times}b[/tex]
=[tex]10{\times}12=120cm^{2}[/tex]
Area of triangles CIH and DIG= [tex]2{\times}\frac{1}{2}{\times}b{\times}h[/tex]
=[tex]6{\times}8=48cm^{2}[/tex]
Surface area of the triangular prism=Area of rectangle ABCD+Area rectangle CDHG+Area rectangle HGFE+Area of triangles CIH and DIG
=[tex]72+96+120+48=336cm^{2}[/tex]
Hence, option C is correct.