Split the second term in 2x^2 - x - 6 into two terms
2x^2 + 3x - 4x - 6
Factor out common terms in the first two terms, then in the last two terms
x(2x + 3) - 2(2x + 3)
Factor out the common term 2x + 3
(2x + 3)(x - 2)
Answer:
(2x + 3) (x - 2 )
Step-by-step explanation:
2x^2 -x -6
(2x 3) (x 2 )
3*2 = 6 so one of the must be negative
2x*2 3x
Which one should be negative. We want to end up with negative x so 2x*2 should be negative
