Answer: 9300 kcal
Explanation: Given: Latent heat of fusion of aluminum is 93 kcal/kg.
That is for melting 1 kg of aluminium at 660[tex]^0C[/tex] amount of heat required is = 93kcal
Thus for 100 kg of aluminium at 660[tex]^0C[/tex] amount of heat required is= [tex]\frac{93}{1}\times 100=9300kcal[/tex]
Thus the amount of energy needed to melt 100 kg of aluminum at the melting point is 9300 kcal.
