In a triangle ,shortest leg is located in the coordinate plane at B (-2,4) and C(-6,0).
Distance between two points in two dimensional plane is given by =[tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2[/tex]
BC= [tex]\sqrt{(-2 +6)^2+(4-0)^2}=\sqrt{16+16}=\sqrt{32}=4\sqrt{2}[/tex]
= 4 × 1.414
= 5.656
Let A (p,q), be the Third vertex of ΔA BC.There will be no single point. We can find the locus of point A.
Equation of line BC is :
[tex]\frac{y-0}{x+6}=\frac{4-0}{-2+6} \\\\ y= x +6[/tex]
So,the third point that is Locus of point A ,will be no point lying on the line, →y= x +6.
Also, A Triangle is formed, when
Sum of two sides of triangle is greater than third side.
So,third point A will be such that,
1. AB +AC> BC
2. AB +BC> AC
3. AC +BC> AB
(-2, -8)
Step-by-step explanation:
The similarity ratio is 2.
All corresponding sides of similar triangles are proportional.
