A fruit stand has to decide what to charge for their produce. They need \$10$10 for 44 apples and 44 oranges. They also need \$15$15 for 66 apples and 66 oranges. We put this information into a system of linear equations. Can we find a unique price for an apple and an orange?

Respuesta :

Answer:

We can't find a unique price for an apple and an orange.

Step-by-step explanation:

Suppose, the price of an apple is [tex]x[/tex] and the price of an orange is [tex]y[/tex]

They need $10 for 4 apples and 4 oranges. So, the first equation will be.......

[tex]4x+4y=10 ........................................(1)[/tex]

They also need $15 for 6 apples and 6 oranges. So, the second equation will be........

[tex]6x+6y= 15 ........................................(2)[/tex]

Dividing equation (1) by 2 on both sides :  [tex]2x+2y= 5[/tex]

Dividing equation (2) by 3 on both sides :  [tex]2x+2y=5[/tex]

So, we can see that both equation (1) and (2) are actually same. That means, we will not get any unique solution for [tex]x[/tex] and [tex]y[/tex] here. Both [tex]x[/tex] and [tex]y[/tex] have "infinitely many solutions".

Thus, we can't find a unique price for an apple and an orange.

Answer:

no;has many solutions

Step-by-step explanation:

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