Answer:
2 complex roots
Step-by-step explanation:
To find the number of real roots for a quadratic, we apply the discriminate. The discriminate is the inside portion of the square root from the quadratic formula.
• [tex]b^2-4ac>0[/tex] yields 2 real roots
• [tex]b^2-4ac=0[/tex] yields 1 real root
• [tx]b^2-4ac<0[/tex] yields no real roots
[tex]x^2-6x+12=0[/tex] where a=1, b=-6, and c=12
[tex]b^2-4ac=(-6)^2-4(1)(12)=36-48=-12<0)[/tex] has no real roots
Answer:
Step-by-step explanation:
Solving gives you an problem with an i in it when using quadratic. Therefore it is a + and - and are complex. 2 complex roots
