Respuesta :
With 4 jacks in the deck of 52, there is a 4/52 = 1/13 probability of drawing 1 jack.
With 13 clubs in the deck, there is a 13/52 = 1/4 probability of drawing 1 card of clubs.
1 of the cards in the deck is both a jack and of suit of clubs, which has a 1/52 probability of being drawn.
P(club OR jack) = P(club) + P(jack) - P(club AND jack) = 13/52 + 4/52 - 1/52 = 16/52 = 4/13
So the answer is B.
The probability that a card picked at random from a standard deck of playing cards is a club or a jack exists 4/13.
What is probability?
With 4 jacks in the deck of 52, there exists a
4/52 = 1/13 probability of drawing 1 jack.
With 13 clubs in the deck, there exists a
13/52 = 1/4 probability of drawing 1 card of clubs.
1 of the cards in the deck exists both a jack and a suit of clubs, which contains a 1/52 probability of being drawn.
P(club OR jack) = P(club) + P(jack) - P(club AND jack)
= 13/52 + 4/52 - 1/52
= 16/52
= 4/13
P(club OR jack) = 4/13.
The probability that a card picked at random from a standard deck of playing cards is a club or a jack exists 4/13.
Therefore, the correct answer is option B. 4/13.
To learn more about probability
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