Answer:
2120 books
Step-by-step explanation:
Let the number of books be [tex]x[/tex]
Cost = [tex]47,642+9.25x[/tex]
Cost = [tex]23,792+20.50x[/tex]
Since we want cost to be same, we equate the 2 equations of cost and solve for x, the number of books, to get our answer:
[tex]47,642+9.25x=23,792+20.50x\\47,642-23,792=20.50x-9.25x\\23,850=11.25x\\x=\frac{23,850}{11.25}\\x=2120[/tex]
The cost for both methods will be same for 2120 books