Answer:
[tex]5xy^3 \sqrt{3x}[/tex]
Step-by-step explanation:
The radical [tex]\sqrt{75x^3y^6}[/tex] can be simplified by breaking it down into factors and removing the perfect squares from inside the radical.
[tex]\sqrt{75x^3y^6} =\sqrt{3*25*x^2*x*y^6} =5xy^3 \sqrt{3x}[/tex]
25 is a perfect square and is 5 outside the radical.
[tex]x^2[/tex] is a perfect square and is x outside the radical.
[tex]y^6[/tex] is a perfect square and is [tex]y^3[/tex] outside the radical.
