Answer:
Vertex
V = (2, -12)
Axis of symmetry
x = 2
Step-by-step explanation:
To answer this question suppose the general equation of a parabola of the form:
[tex]ax^2 + bx + c[/tex]
Where a, b and c are constants that belong to real numbers.
So it is known that the vertex of this parable is:
[tex]x = \frac{-b}{2a}[/tex]
So, we use this same formula to find the vertex of the parabola [tex]y = -2x^2 + 8x-20[/tex]
Where:
[tex]a = -2\\b = 8\\c = -20\\\\x = \frac{-b}{2a}\\\\x = \frac{-8}{2 (-2)}\\\\x = 2[/tex]
The vertex of the parabola is at the point
V = (2, -12)
Finally, the axis of symmetry of a parabola always passes through its vertex. Then the axis of symmetry is the straight line
x = 2
