You would have a 3 to 10 chance that the first 3 cars are in order
Answer:
[tex]\frac{1}{720}[/tex]
Step-by-step explanation:
If we arrange the first three cars one by one we get -
Selecting the first car out of ten cars [tex]= \frac{1}{10}[/tex]
Selecting the second car out of remaining nine cars [tex]= \frac{1}{9}[/tex]
Selecting the third car out of remaining eight cars [tex]= \frac{1}{8}[/tex]
So, the probability of selecting three cars back to back without repeating is given by
Probability of Selecting the first car out of ten cars * Probability of Selecting the second car out of remaining nine cars * Probability of Selecting the third car out of remaining eight cars
[tex]= \frac{1}{10} * \frac{1}{9}* \frac{1}{8}\\= \frac{1}{720}[/tex]
