can anyone show me how I would figure this problem out

The value of x is the number inside the parenthesis, so h(-4) gives x a value of -4.
The equation says when X is ≤ -4 use the first equation
So h(-4) = -1/2(x) -15
= -1/2(-4) -15
= 2 -15
= -13
When x = -2 (h(-2) ) use the 2nd equation:
h(-2) = 20-3x^2
=20-3(-2)^2
= 20-3(4)
=20-12
=8
Now you have -13 + 3(8)
= -13 + 24
=11
The answer should be 11
Answer:
11
Step-by-step explanation:
it means if x =< -4 do
h(x) = - 0.5x - 15
else if x > -4 do
h(x) = 20 - 3x^2
so from the question we need to find the value of h(-4) + 3h(-2)
h(-4) + 3h(-2) = ( - 0.5 * ( -4 ) - 15 ) + 3( 20 - 3( -2 )^2 )
= ( -13 ) + 24 = 11