Answer: The temperature of the gas was 50.46°C.
Explanation:
To calculate the final volume when temperature increases, we use Charles' Law which states that the volume is directly proportional to the temperature of the gas if number of moles and pressure remains constant.
Mathematically,
[tex]V\propto T\\\\\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where,
[tex]V_1\text{ and }T_1[/tex] = Initial volume and temperature
[tex]V_2\text{ and }T_2[/tex] = Final volume and temperature
We are given:
[tex]V_1=178mL\\T_1=0^oC=273K\\V_2=211mL\\T_2=?[/tex]
Putting values in above equation, we get:
[tex]\frac{178}{273}=\frac{211}{T_2}[/tex]
[tex]T_2=323.61K=50.46^oC[/tex] (Conversion factor: T(K) = T(°C) + 273.15)
Hence, the temperature of the gas is 50.46°C
