Answer:
-139 °C
Step-by-step explanation:
We can use the Ideal Gas Law and solve for T.
pV = nRT Divide each side by nR
T = (pV)/(nR)
Data:
p = 3.25 atm
V = 4.738 L
n = 1.4 mol
R = 0.082 06 L·atm·K⁻¹mol⁻¹
Calculation:
T = (3.25 ×4.738)/(1.4 × 0.082 06)
T = 134 K
T = (134 - 273.15) °C
T = -139 °C
The temperature of 1.4 moles of gas’s with pressure of 3.25 atmosphere in a 4.738-liter container will be 134K.
Temperature is a measure of the kinetic energy of the atoms and molecules in any system. Temperature is denoted by symbol T.
The calculation of temperature is shown below:
By using ideal gas law.
PV=nRT.
where, P is pressure, V is volume, n is number of moles, R is gas constant and T is temperature.
It is given that, n = 1.4 moles, P = 3.25 atm, V = 4.738 L. R = 0.082L.atm[tex]K^{-1}mol^{-1}[/tex]
Now, put the values of given data in above formula.
T = PV /nR
= (3.25 × 4.738) / (1.4 × 0.082)
= 134 K.
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