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Consider the reaction between no and cl2 to form nocl: 2no(g)+cl2(g)⇌2nocl(g) a reaction mixture at a certain temperature initially contains only [no]= 0.65 m and [cl2]= 0.53. after the reaction comes to equilibrium, the concentration of nocl is 0.30 m . part a find the value of the equilibrium constant (kc) at this temperature.

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superman1987

Answer:

Kc = 0.402.

Explanation:

  • We can calculate Kc from the relation: Kc = [NOCl]² / [NO]²[Cl₂].
  • [NOCl] = 0.30 M, [NO] = 0.65 M, and [Cl₂] = 0.53 M.
  • Now, we can get Kc:
  • Kc =  [NOCl]² / [NO]²[Cl₂] = (0.30 M)² / [(0.65 M)².(0.53 M)] = 0.402.
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