Answer:
15:
Perimeter = 167
16:
Perimeter= 8x + 18
Step-by-step explanation:
15:
Perimeter of triangle = sum of length of all of its sides
As it is given that
side 1 [tex]=x^{2}-10[/tex]
side 2[tex]=2x^{2}+14[/tex]
side 3 = 5x + 25
and
x= 6
Now
Perimeter =[tex]x^{2}-10+2x^{2}+14+5x + 25[/tex]
putting x = 6
we get
Perimeter =[tex]6^{2}-10+2*(6)^{2}+14+5(6) + 25[/tex]
Perimeter =[tex]36-10+2*36+14+30 + 25[/tex]
Perimeter =[tex]36-10+72+14+30 + 25[/tex]
Solving it gives
Perimeter = 167
16:
Perimeter of the following shape will be sum of all of its sides
So
Perimeter = (4x - 5 ) + (x-4) + (x+6)+(x+3)+(2x+3)+(x+15)
= 4x -5 +x -4 + x + 6 + x + 3 + 2x + 3 + x + 15
=4x + x +x+2x+x-5-4+6+3+3+15
=8x + 18
So
Perimeter = 8x + 18
