[tex]( \frac{16}{2} )^{ \frac{1}{2} } = 2 {}^{x} [/tex]
And if we know
[tex]16 \div 2 = 8[/tex]
So that means
[tex] {8}^{ \frac{1}{2} } = {2}^{x} [/tex]
We also know that
[tex]2 \times 2 \times 2 = 8[/tex]
Which is equivalent to
[tex] {2}^{3} = 8[/tex]
So if we rewrite the equation with this...
[tex]2 {}^{3 \times \frac{1}{2} } = {2}^{x} [/tex]
So that means
[tex]3 \times \frac{1}{2} = x[/tex]
[tex]x = \frac{3}{2} [/tex]
And we get to the end result that
[tex]( \frac{16}{2} ) {}^{ \frac{1}{2} } = 2 {}^{ \frac{3}{2} } [/tex]
