48y^5=27y^3
subtract 27 y^3 from each side
48y^5-27y^3=0
factor out 3y^3
3y^3(16y^2 -9)=0
factor
3y^3 (4y-3) (4y+3) =0
using the zero product property
3y^3 =0 4y-3 =0 4y+3 =0
y^3=0 4y=3 4y = -3
y=0 y = 3/4 y = -3/4
Answer: y = -3/4, 0, 3/4
