log(t-3)=log(17-4t)
since they are both logs to the same base, what is inside must be the same
t-3 = 17 -4t
add 4t to each side
t-3+4t = 17-4t+4t
5t-3 = 17
add 3 to each side
5t -3+3 = 17+3
5t = 20
divide each side by 5
t =4
[tex]\text{The domain}\\\\t-3 > 0\ \wedge\ 17-4t > 0\\\\t > 3\ \wedge\ t < \dfrac{17}{4}\to3<t<4\dfrac{1}{4}\\--------------------------------\\\\\log(t-3)=\log(17-4t)\iff t-3=17-4t\qquad\text{add 3 to both sides}\\\\t=20-4t\qquad\text{add 4t to both sides}\\\\5t=20\qquad\text{divide both sides by 5}\\\\\boxed{t=4}\in Domain[/tex]