Answer:
Triangle ACB is similar to Triangle DEF by SAS Similarity Theorem
see the explanation
Step-by-step explanation:
we know that
The SAS Similarity Theorem, states that: If an angle of one triangle is congruent to the corresponding angle of another triangle and the lengths of the sides including these angles are in proportion, then the triangles are similar.
In this problem
Angle B and Angle F are congruent
∠B≅∠F
The corresponding sides are
BC and FE
and
AB and DF
Verify if the ratios are proportional
[tex]\frac{BC}{FE}=\frac{AB}{DF}[/tex]
substitute the given values
[tex]\frac{24}{16}=\frac{12}{8}[/tex]
[tex]1.5=1.5[/tex] -----> is true
therefore
Triangles ACB and DEF are similar by SAS Similarity Theorem
