For this case we have that by definition, let [tex]y = f (x)[/tex], to find the intercept with the "y" axis of a line, we must replace [tex]x = 0[/tex]and solve [tex]y = f (0).[/tex] Thus, the intersection with the "y" axis will be given by the point [tex](0, f (0)).[/tex]
If we have [tex]y = f (x) = \frac {-6} {13} x + 11[/tex]
To find the intersection with the "y" axis, we make f (0), then:
[tex]f (0) = \frac {-6} {13} (0) +11\\f (0) = 11[/tex]
So, y-intercept: [tex](0,11)[/tex]
Answer:
the y-intercept of the line with the equation [tex]y = \frac {-6} {13} x + 11[/tex] is: 11
Option C
